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TS EAMCET · Physics · Oscillations

A particle is executing simple harmonic motion (S.H.M.). Its acceleration at a distance of 1 cm from the mean position is 3 cm s-2. If its velocity is 6 cm s-1 when it is at a distance of 2 cm from its mean position, then the amplitude of S.H.M. is, 

  1. A 5 cm
  2. B 4 cm
  3. C 23 cm
  4. D 32 cm
Verified Solution

Answer & Solution

Correct Answer

(B) 4 cm

Step-by-step Solution

Detailed explanation

Recall the proper formula of acceleration and velocity in terms of amplitude and angular velocity, a=-ω2x and v=ωA2-x2, given, x=1 cm & a=3 cm s-2, it means the value of, ω=ax=31 , and the velocity,…
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