TS EAMCET · Maths · Three Dimensional Geometry
Let \(\mathrm{A}(2,5,7)\) be the image of the point \(\mathrm{B}(1,-2,3)\) with respect to a plane \(\pi\). Let \(C\) be the point where \(A B\) meets the plane \(\pi\). Let \(\mathrm{D}=(2,1,6)\). Then the direction cosines of \(\mathrm{CD}\) are
- A \(\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}}\)
- B \(\frac{1}{\sqrt{6}}, \frac{-1}{\sqrt{6}}, \frac{2}{\sqrt{6}}\)
- C \(\frac{3}{\sqrt{46}}, \frac{-1}{\sqrt{46}}, \frac{6}{\sqrt{46}}\)
- D \(\frac{1}{\sqrt{14}}, \frac{2}{\sqrt{14}}, \frac{3}{\sqrt{14}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{6}}, \frac{-1}{\sqrt{6}}, \frac{2}{\sqrt{6}}\)
Step-by-step Solution
Detailed explanation
Given point \(\mathrm{B}(1,-2,3)\) having image \(\mathrm{A}(2,5,7)\) with respect to the plane \(\pi\) hence DRs of point \(\mathrm{C}\) is \(\left(\frac{1}{2},-\frac{1}{2}, 1\right)\) Now DEs of CD are…
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