TS EAMCET · Maths · Circle
The line \(y=m x+c\) intercepts the circle \(x^2+y^2=r^2\) in two distinct points, if
- A \(-r \sqrt{1+m^2} < c < r \sqrt{1+m^2}\)
- B \(c < -r \sqrt{1+m^2}\)
- C \(c < r \sqrt{1+m^2}\)
- D None of the above
Answer & Solution
Correct Answer
(A) \(-r \sqrt{1+m^2} < c < r \sqrt{1+m^2}\)
Step-by-step Solution
Detailed explanation
Equation of the circle is \[ x^2+y^2=r^2 \] and the line is \(m x-y+c=0\) The line (ii) intersect (i) in two distinct points, if the length of the \(\perp^r\) from the centre \((0,0)\) to the line (ii) is less then \(r\) Thus, \(\left|\frac{0-0+c}{\sqrt{m^2+1}}\right| < r\)…
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