TS EAMCET · Maths · Vector Algebra
\(\mathbf{a}\) is perpendicular to both \(\mathbf{b}\) and \(\mathbf{c}\). The angle between \(\mathbf{b}\) and \(\mathbf{c}\) is \(\frac{2 \pi}{3}\). If \(|\mathbf{a}|=2\), \(|\mathbf{b}|=3,|\mathbf{c}|=4\), then \(\mathbf{c} \cdot(\mathbf{a} \times \mathbf{b})\) is equal to
- A \(18 \sqrt{3}\)
- B \(12 \sqrt{3}\)
- C \(8 \sqrt{3}\)
- D \(6 \sqrt{3}\)
Answer & Solution
Correct Answer
(B) \(12 \sqrt{3}\)
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