TS EAMCET · Maths · Circle
The equation of the pair of transverse common tangents drawn to the circles \(x^2+y^2+2 x+2 y+1=0\) and \(x^2+y^2-2 x-2 y+1=0\) is
- A \(x^2-y^2=0\)
- B \(x^2-y^2+2 x+1=0\)
- C \(x y=0\)
- D \(x^2-y^2-2 y-1=0\)
Answer & Solution
Correct Answer
(B) \(x^2-y^2+2 x+1=0\)
Step-by-step Solution
Detailed explanation
\(S_1 \equiv x^2+y^2+2 x+2 y+1=0\) \(S_2=x^2+y^2-2 x-2 y+1=0\) Centre of \(S_1\left(C_1\right)=(-1,-1)\). Centre of \(S_2\left(C_2\right)=(1,1)\) \(r_1=1, r_2=1, C_1 C_2 \gt r_1+r_2\) Let \(P(x, y)\) be the point of intersection of common tangents…
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