TS EAMCET · Maths · Application of Derivatives
The equation of the tangent to the curve at the point where it crosses -axis is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
Given equation of curve y=πe-xπ.....................i Let the point P0,y1, where tangent to curve crosses y-axis. Putting x=0, in equation i, y1=π Differentiate equation i w. r. t. x ddxy=ddxπe-xπ dydx=πe-xπ.-1π dydx0,y1=-1 So, the…
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