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TS EAMCET · Maths · Limits

If \(\log (1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+\ldots \ldots \infty\) and \(\lim _{x \rightarrow 0} \frac{\log (1+x)^{1+x}}{x^2}-\frac{1}{x}=k\), then \(12 k=\)

  1. A 1
  2. B 3
  3. C 6
  4. D 9
Verified Solution

Answer & Solution

Correct Answer

(C) 6

Step-by-step Solution

Detailed explanation

We have, \(\lim _{x \rightarrow 0} \frac{\log (1+x)^{1+x}}{x^2}-\frac{1}{x}=k\) \(\begin{array}{ll} \Rightarrow & \lim _{x \rightarrow 0} \frac{(1+x) \log (1+x)-x}{x^2}=k \\ \Rightarrow & \lim _{x \rightarrow 0} \frac{\log (1+x)+1-1}{2 x}-=k \end{array}\) [using L' Hospital…