TS EAMCET · Maths · Probability
Ten persons with badges numbered 1 to 10 are in a room. If three of them are asked to leave the room. Then, the probability to have the person with the smallest badge number as 5 among the three persons that left the room, is
- A \(\frac{3}{10}\)
- B \(\frac{1}{6}\)
- C \(\frac{1}{12}\)
- D \(\frac{2}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{12}\)
Step-by-step Solution
Detailed explanation
Let \(S\) be the event of selecting 3 number from first 10 natural number \[ \therefore \quad n(s)={ }^{10} C_3 \] Let \(A\) be the event of selecting three number from 1 to 10 number out of which the smallest number is 5 .…
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