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TS EAMCET · Maths · Parabola

If the tangent drawn at the point \(P(4,8)\) to the parabola \(y^2=16 x\) meets the parabola \(y^2=16 x+80\) at \(A\) and \(B\), then the mid-point of \(A B\) is

  1. A \((9,6)\)
  2. B \((4,8)\)
  3. C \((4,1)\)
  4. D \((2,3)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((4,8)\)

Step-by-step Solution

Detailed explanation

Equation of tangent to the parabola \(y^2=16 x\) at point \(P(4,8)\) is \(8 y=8(x+4) \Rightarrow y=x+4\) \(\ldots(\mathrm{i})\) \(\because\) Tangent (i) meets the another parabola \(y^2=16 x+80\) at \(A\) and \(B\), so on solving them we have \((x+4)^2=16 x+80\)…