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TS EAMCET · Maths · Differentiation

If \(x^2+y^2=t+\frac{1}{t}, x^4+y^4=t^2+\frac{1}{t^2}\), then \(x^3 y \frac{d y}{d x}\) is equal to

  1. A \(-1\)
  2. B \(1\)
  3. C \(0\)
  4. D \(t\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(-1\)

Step-by-step Solution

Detailed explanation

Given, \(x^4+y^4=t^2+\frac{1}{t^2}\)…