TS EAMCET · Maths · Ellipse
Let \(A\) be a vertex of the ellipse \(S \equiv \frac{x^2}{4}+\frac{y^2}{9}-1=0\) and \(F\) be a focus of the ellipse \(S^{\prime} \equiv \frac{x^2}{9}+\frac{y^2}{4}-1=0\). Let \(P\) be a point on the major axis of the ellipse \(S^{\prime}=0\), which divides \(\overline{O F}\) in the ratio \(2: 1\) ( \(O\) is the origin). If the length of the chord of the ellipse \(S=0\) through \(A\) and \(P\) is \(\frac{3 \sqrt{101}}{k}\), then \(k=\)
- A 5
- B 4
- C 7
- D 8
Answer & Solution
Correct Answer
(C) 7
Step-by-step Solution
Detailed explanation
We have, \(\quad S \equiv \frac{x^2}{4}+\frac{y^2}{9}=1\) \[ \therefore \quad A(0, \pm 3) \quad \text { (vertex }=(0, \pm b) \] Again,…
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