TS EAMCET · Maths · Vector Algebra
Let \(\vec{a}=\hat{i}+2 \hat{j}-2 \hat{k}\) and \(\vec{b}=2 \hat{i}-\hat{j}-2 \hat{k}\) be two vectors. If the orthogonal projection vector of \(\vec{a}\) on \(\vec{b}\) is \(\vec{x}\) and orthogonal projection vector of \(\vec{b}\) on \(\vec{a}\) is \(\vec{y}\) then \(|\vec{x}-\vec{y}|=\)
- A \(\frac{4}{9} \sqrt{10}\)
- B \(\frac{4}{9} \sqrt{26}\)
- C \(\frac{8}{9} \sqrt{10}\)
- D \(\frac{8}{9} \sqrt{26}\)
Answer & Solution
Correct Answer
(A) \(\frac{4}{9} \sqrt{10}\)
Step-by-step Solution
Detailed explanation
Orthogonal projection of \(\vec{a}\) on \(\vec{b}=\frac{(\vec{a} \cdot \vec{b})}{|\vec{b}|^2} \vec{b}\) \(\therefore \vec{x}=\frac{4}{9} \vec{b}\) Orthogonal projection of \(\vec{b}\) on \(\vec{a}=\frac{(\vec{a} \cdot \vec{b})}{|\vec{a}|^2} \vec{a}\)…
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