TS EAMCET · Maths · Three Dimensional Geometry
If \(l, m, n\) are the d.c's of a normal to the plane passing through the points \((0,1,2),(3,0,2),(4,5,0)\) then \(|l|+|m|+|n|=\)
- A \(\frac{13}{\sqrt{91}}\)
- B \(\frac{11}{\sqrt{57}}\)
- C \(\frac{13}{\sqrt{77}}\)
- D \(\frac{12}{\sqrt{74}}\)
Answer & Solution
Correct Answer
(D) \(\frac{12}{\sqrt{74}}\)
Step-by-step Solution
Detailed explanation
The plane passing through points \((0,1,2)(3,0,2)\), \((4,5,0)\) can be given as \(2 x+6 y+16 z-38=0\) Now \(|1|+|\mathrm{m}|+|\mathrm{n}|=\frac{12}{\sqrt{74}}\)
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