TS EAMCET · Maths · Indefinite Integration
If \(\int(3 x+2) \sqrt{2 x^2+3 x+4} d x=f(x)\) \(\sqrt{2 x^2+3 x+4}+A \sinh ^{-1}\left(\frac{4 x+3}{\sqrt{23}}\right)+C\), then the ordered pair \((f(\mathbf{l}), A)=\)
- A \(\left(\frac{73}{8}, \frac{23}{64 \sqrt{2}}\right)\)
- B \(\left(\frac{137}{32}, \frac{-23}{64 \sqrt{2}}\right)\)
- C \(\left(\frac{15}{8}, \frac{-23}{16 \sqrt{2}}\right)\)
- D \(\left(\frac{49}{32}, \frac{23}{16 \sqrt{2}}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{137}{32}, \frac{-23}{64 \sqrt{2}}\right)\)
Step-by-step Solution
Detailed explanation
Let \(I=\int(3 x+2) \sqrt{2 x^2+3 x+4} d x\) \(\begin{aligned} & \text { Put, } 3 x+2=\lambda(4 x+3)+\mu \\ & \Rightarrow \quad 3=4 \lambda \text { and } 2=3 \lambda+\mu\end{aligned}\) \(\therefore \quad \lambda=\frac{3}{4}, \mu=\frac{-1}{4}\)…
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