TS EAMCET · Maths · Parabola
An equilateral triangle is inscribed in the parabola \(y^2=16 a x\) with one of its vertices at the origin. Then, the centroid of that triangle is
- A \((8 a, 0)\)
- B \((16 a, 0)\)
- C \((32 a, 0)\)
- D \((48 a, 0)\)
Answer & Solution
Correct Answer
(C) \((32 a, 0)\)
Step-by-step Solution
Detailed explanation
Let the length at one side is \(l\), so coordinate of \(A\) is \(\left(\frac{\sqrt{3} l}{2}, \frac{l}{2}\right)\) lies on parabola so in \(y^2=16 a x\)…
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