TS EAMCET · Maths · Pair of Lines
Let \(3 x^2+8 x y-3 y^2=\) are present the lines \(L_1\), \(L_2\) and \(3 x^2+8 x y-3 y^2+2 x-4 y-1=0\) represent the lines \(L_3, L_4\). Let \(L\) be the line joining the points of intersection of \(L_1, L_3\) and \(L_2, L_4\). Then, the area (in sq units) of the triangle formed by \(L\) with the coordinate axes is
- A \(\frac{1}{2}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{8}\)
- D \(\frac{1}{16}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{16}\)
Step-by-step Solution
Detailed explanation
We have, \[ 3 x^2+8 x y-3 y^2=0 \] and \(3 x^2+8 x y-3 y^2+2 x-4 y-1=0\) \(L\) be the line joining the intersection point of the pairs of straight lines.…
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