TS EAMCET · Maths · Differential Equations
The general solution of \(\frac{d y}{d x}=\frac{x^3\left(y^4+1\right)}{[}\) is \[ \left[2 y^{-\frac{2}{3}}+3\left(\frac{x}{\sqrt[3]{y}}\right)^2\right]^{\frac{3}{2}} \]
- A \(\log \left(\frac{y^4}{1+y^4}\right)=\frac{4}{9}\left(\frac{4+3 x^2}{\sqrt{2+3 x^2}}\right)+C\)
- B \(\frac{1}{4} \log \left(\frac{y^4}{1+y^4}\right)=\frac{1}{9} \log \left(\frac{4+3 x^2}{\sqrt{2+3 x^2}}\right)+C\)
- C \(\frac{1}{4} \log \left(\frac{y^4}{1+y^4}\right)=\frac{4}{9} \frac{1}{\sqrt{2+3 x^2}}+C\)
- D \(\log \left(\frac{y^4}{1+y^4}\right)=\frac{1}{9} \frac{1}{\sqrt{2+3 x^2}}+C\)
Answer & Solution
Correct Answer
(A) \(\log \left(\frac{y^4}{1+y^4}\right)=\frac{4}{9}\left(\frac{4+3 x^2}{\sqrt{2+3 x^2}}\right)+C\)
Step-by-step Solution
Detailed explanation
Given, \(\begin{aligned} \frac{d y}{d x} & =\frac{x^3\left(y^4+1\right)}{\left[2 y^{-\frac{2}{3}}+3\left(\frac{x}{\sqrt[3]{y}}\right)^2\right]^{3 / 2}} \\ & =\frac{x^3\left(y^4+1\right)}{\left[2 y^{-2 / 3}+3 x^2 y^{-2 / 3}\right]^{3 / 2}}\end{aligned}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- The value \(C\) of the Lagrange's mean value theorem for the function \(f(x)=x(x-1)(x-2)\) in the interval \(\left[0, \frac{1}{2}\right]\) isTS EAMCET 2018 Easy
- \(\int_0^{\pi / 4} x^2 \sin 2 x d x=\)TS EAMCET 2025 Medium
- The value of \(\cos \frac{2 \pi}{15} \cos \frac{4 \pi}{15} \cos \frac{8 \pi}{15} \cos \frac{14 \pi}{15}\) is :TS EAMCET 2003 Easy
- There are red and yellow roses of different sizes. If is the number of garlands that can be formed with all these flowers so that no two yellow roses come together and is the number of garlands formed with all these flowers so that all the red roses coming together, thenTS EAMCET 2020 Medium
- If , then isTS EAMCET 2018 Medium
- If \(\alpha, \beta, \gamma\) are the roots of the equation \(x^3+3 x^2-x-3=0\), then \(\left(1+\alpha^2\right)\left(1+\beta^2\right)\left(1+\gamma^2\right)=\)TS EAMCET 2020 Easy
More PYQs from TS EAMCET
- If \(f: R \rightarrow R\) is defined by \(f(x)=\left\{\begin{array}{ccc} \frac{x+2}{x^2+3 x+2} & \text { if } & x \in R-\{-1,-2\} \ -1 & \text { if } & x=-2 \ 0 & \text { if } & x=-1 \end{array}\right.\) then \(f\) is continuous on the setTS EAMCET 2005 Medium
- Statement (I) : The slope of kinetic energy-displacement curve of a body in motion will be directly proportional to its acceleration. Statement (II) : From a height of \(15 \mathrm{~m}\) a ball is projected vertically upwards with a velocity of \(30 \mathrm{~m} / \mathrm{s}\). If the ball rises to the same height after hitting the ground, the loss of its energy on hitting the ground is \(30 \%\). Statement (III) : The velocity acquired by a body of mass ' \(m\) ' after travelling a fixed distance from rest under the action of a constant force is directly proportional to mass ' \(\mathrm{m}\) '. Which of the following is correct?TS EAMCET 2022 Medium
- When the right gap of a meter bridge consists of two equal resistors in series, the balancing point is at 50 cm. When one of the resistors in the right gap is removed and is connected in parallel to the resistor in the left gap, the balancing point is atTS EAMCET 2025 Medium
- The \(C_p\) of an ideal gas is \(10.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\). One mole of this gas is expanded against a constant pressure of p atm. The change in temperature during expansion is 1.0 K. The values of q (in J ) and \(\Delta \mathrm{H}\) (in \(\mathrm{J} \mathrm{mol}^{-1}\) ) are respectivelyTS EAMCET 2025 Medium
- All the letters of the word 'COLLEGE' are arranged in all possible ways and all the seven letter words (with or without meaning) thus formed are arranged in the dictionary order. Then the rank of the word 'COLLEGE' isTS EAMCET 2024 Easy
- The coefficient of in the expansion of isTS EAMCET 2021 Easy