TS EAMCET · Maths · Probability
Let \(\mathrm{P}=\left[\begin{array}{lll}1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9\end{array}\right]\) be a matrix. Three elements of this matrix P are selected at random. A is the event of having the three elements whose sum is odd. B is the event of selecting the three elements which are in a row or column. Then \(\mathrm{P}(\mathrm{A})+\mathrm{P}\left(\frac{\mathrm{A}}{\mathrm{B}}\right)=\)
- A \(\frac{221}{420}\)
- B \(\frac{17}{21}\)
- C \(\frac{21}{20}\)
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{17}{21}\)
Step-by-step Solution
Detailed explanation
Total elements \(N = 9\). Total ways to select 3 elements: \(\binom{9}{3} = 84\). Odd numbers (O): {1, 3, 5, 7, 9} (5 elements). Even numbers (E): {2, 4, 6, 8} (4 elements). Event A: Sum of three elements is odd. Case 1: OOO: \(\binom{5}{3} = 10\). Case 2: OEE:…
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