TS EAMCET · Maths · Limits
If \(f\) is a real function such that \(f(4)=4\) and \(f^{\prime}(4)=16\), then \(\lim _{x \rightarrow 4} \frac{\sqrt{f(x)}-2}{\sqrt{x}-2}=\)
- A 16
- B 12
- C 8
- D 2
Answer & Solution
Correct Answer
(A) 16
Step-by-step Solution
Detailed explanation
We have, \(f(4)=4\) and \(f^{\prime}(4)=16\) Now, consider \(\lim _{x \rightarrow 4} \frac{\sqrt{f(x)}-2}{\sqrt{x}-2} \quad\left[\frac{0}{0}\right.\) form \(]\)…
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