TS EAMCET · Maths · Three Dimensional Geometry
\(L\) is a line passing through the point \(A(1,0,-3)\) and parallel to a line having direction ratios \(0,1,-2 P\) is a point on the line \(L\) which is at a minimum distance from the plane \(2 x+3 y+5 z=1\). Then, the equation of the plane through \(P\) and perpendicular to \(A P\) is
- A \(y+2 z=12\)
- B \(y-2 z+4=0\)
- C \(x+y-2 z=12\)
- D \(2 y-z=16\)
Answer & Solution
Correct Answer
(B) \(y-2 z+4=0\)
Step-by-step Solution
Detailed explanation
Equation of line \(L\) is \(\frac{x-1}{0}=\frac{y-0}{1}=\frac{z+3}{-2}=\lambda\) (say) Then, any point on \(L\) is of the form \((1, \lambda,-2 \lambda-3)\). Now, the distance of \((1, \lambda,-2 \lambda-3)\) from the plane \(2 x+3 y+5 z=1\) is…
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