TS EAMCET · Maths · Circle
The locus of the mid points of the chords of the circle drawn from a point on it is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
Equation of chord of circle S≡x2+y2+2gx+2fy+c=0 in terms of the mid point Mx1,y1 is y-y1=-x1+gy1+fx-x1 which is designated by T=S1. Now compare the given equation of circle with S≡x2+y2+2gx+2fy+c=0 we get g=-1,f=0 Now, y-y1=-x1+gy1+fx-x1 -y1=-x1-1y1-x1 -y12=x12-x1…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \(f(x)= \begin{cases}\frac{1-\sqrt{2} \sin x}{\pi-4 x} & \text { if } x \neq \frac{\pi}{4} \ a & \text { if } x=\frac{\pi}{4}\end{cases}\) is continuous at \(\frac{\pi}{4}\), then \(a\) is equal toTS EAMCET 2006 Easy
- If \(2 x^2+3 x y-y^2+4 x-5 y+6=0\), then the value of \(\frac{d y}{d x}\) at \((x, y)=(1,-2)\) isTS EAMCET 2023 Easy
- A point \(P\) moves so that distance from \((0,2)\) to \(P\) is \(\frac{1}{\sqrt{2}}\) times the distance of \(P\) from \((-1,0)\). Then the locus of the point isTS EAMCET 2020 Easy
- If the pair of lines given by \(\left(x^2+y^2\right) \cos ^2 \theta=(x \cos \theta+y \sin \theta)^2 \quad\) are perpendicular to each other, then \(\theta\) is equal toTS EAMCET 2012 Medium
- A vector of magnitude \(\sqrt{2}\) units along the internal bisector of the angle between the vectors \(2 \hat{i}-2 \hat{j}+\hat{k}\) and \(\hat{i}+2 \hat{j}+2 \hat{k}\) isTS EAMCET 2024 Easy
- The centroid of the triangle formed by the lines \(x+y=1\) and \(2 y^2-x y-6 x^2=0\) isTS EAMCET 2020 Medium
More PYQs from TS EAMCET
- In \(n-p-n\) transistor, in CE configuration: 1. The emitter is heavily doped than the collector. 2. Emitter and collector can be interchanged. 3. The base region is very thin but is heavily doped. 4. The conventional current flows from base to emitter.TS EAMCET 2004 Easy
- A planet is revolving around the sun in which of the following is correct statement?
TS EAMCET 2020 Medium - Statement (S) : Using Huygen's eye-piece measurements can be taken but are not correct. Reason (R) : The cross wires, scale and final image are not magnified proportionately because the image of the object is magnified by two lenses, whereas the cross wire scale is magnified by one lens only. Identify the correct one of the followingTS EAMCET 2008 Easy
- The set containing the elements with positive electron gain enthalpies isTS EAMCET 2024 Easy
- If \(\mathrm{A}+\mathrm{B}+\mathrm{C}=\frac{\pi}{2}\), then \[ \sqrt{2} \cos \left(\frac{\pi}{4}-A\right)+\sqrt{2} \cos \left(\frac{\pi}{4}-B\right)+\sqrt{2} \cos \left(\frac{\pi}{4}-C\right)+1= \]TS EAMCET 2022 Hard
- A cyclist is riding with a speed of \(36 \mathrm{~km} / \mathrm{h}\). As he approaches a circular turn on the road of radius \(50 \mathrm{~m}\), he applies brakes and reduces his speed at the constant rate of \(0.5 \mathrm{~m} / \mathrm{s}\) every second. The magnitude and direction of the net acceleration of the cyclist on the circular turn respectively areTS EAMCET 2022 Hard