TS EAMCET · Maths · Differential Equations
The differential equation of which \(x y=a e^x+b e^{-x}+x^2\) is a solution, is
- A \(x y^{\prime \prime}-2 y^{\prime}+x y+x^2-2=0\)
- B \(x y^{\prime \prime}+2 y^{\prime}-x+x^2+2=0\)
- C \(x y^{\prime \prime}+2 y^{\prime}-y+x^2-2=0\)
- D \(x y^{\prime \prime}+2 y^{\prime}-x y+x^2-2=0\)
Answer & Solution
Correct Answer
(D) \(x y^{\prime \prime}+2 y^{\prime}-x y+x^2-2=0\)
Step-by-step Solution
Detailed explanation
We have, \(x y=a e^x+b e^{-x}+x^2\) \(\therefore \quad y+x \frac{d y}{d x}=a e^x-b e^{-x}+2 x\) \(\Rightarrow \quad \frac{d y}{d x}+x \frac{d^2 y}{d x^2}+\frac{d y}{d x}=a e^x+b e^{-x}+2\) From Eqs. (i)and (iii), we get \(x \frac{d^2 y}{d x^2}+2 \frac{d y}{d x}=x y-x^2+2\)…
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