TS EAMCET · Maths · Limits
If \(\{x\}=x-[x]\) where \([x]\) is the greatest integer \(\leq x\) and \(\lim _{x \rightarrow 0^{-}} \frac{\operatorname{Cos}^{-1}\left(1-\{x\}^2\right) \operatorname{Sin}^{-1}(1-\{x\})}{\{x\}-\{x\}^4}=\theta\), then \(\tan \theta=\)
- A \(\frac{1}{\sqrt{3}}\)
- B \(1\)
- C \(\sqrt{3}\)
- D \(\infty\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
As \( x \rightarrow 0^{-} \), \( [x] = -1 \). Thus, \( \{x\} = x - (-1) = x+1 \). Let \( y = \{x\} \). Then \( y \rightarrow 1^{-} \). Let \( h = 1-y \). As \( y \rightarrow 1^{-} \), \( h \rightarrow 0^{+} \).…
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