TS EAMCET · Maths · Straight Lines
\(\beta\) is the angle made by the perpendicular drawn from origin to the line \(L \equiv x+y-2=0\) with the positive \(X\)-axis in the anticlockwise direction. If ' \(a\) ' is the \(X\)-intercept of the line \(L=0\) and \(p\) is the perpendicular distance from the origin to the line \(L=0\), then \(a \tan \beta+p^2=\)
- A 1
- B 2
- C 3
- D 4
Answer & Solution
Correct Answer
(D) 4
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & x+y-2=0 \Rightarrow a-2=0 \Rightarrow a=2 \\ & \beta=45^{\circ} \Rightarrow P=2 \cos \beta=\sqrt{2} ; a \tan \beta+P^2=2 \times 1+2=4\end{aligned}\)
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