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TS EAMCET · Physics · Atomic Physics

The ratio of maximum to minimum wavelength in Balmer series of an hydrogenic atom is

  1. A \(\frac{9}{5}\)
  2. B \(\frac{12}{7}\)
  3. C \(\frac{9}{7}\)
  4. D \(\frac{14}{9}\)
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Answer & Solution

Correct Answer

(A) \(\frac{9}{5}\)

Step-by-step Solution

Detailed explanation

Wavelength of spectral lines of Hydrogen like atom is given as \(\frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)\) For Balmer series, \(n_1=2\) and \(n_2=3,4,5,6, \ldots\). \(\frac{1}{\lambda}=R\left(\frac{1}{2^2}-\frac{1}{n_2^2}\right)\)...(i) For minimum…
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