TS EAMCET · Maths · Parabola
If one end of a focal chord of the parabola \(y^2=\frac{8}{a} x(a>0)\) is at \((1,4)\), then the length of this focal chord is
- A \(\frac{25}{8}\)
- B \(\frac{25}{2}\)
- C \(\frac{25}{4}\)
- D 25
Answer & Solution
Correct Answer
(D) 25
Step-by-step Solution
Detailed explanation
We have \(\mathrm{y}^2=(8 / \mathrm{a}) \mathrm{x}\) Since point \((1,4)\) lies on the given curve \[ \Rightarrow \mathrm{a}=\frac{1}{2} \] or equation will be \(\mathrm{y}^2=16 \mathrm{x}\) where \(\mathrm{a}^{\wedge}=4\) Let \(\mathrm{y}^2=4 \mathrm{a}^` \mathrm{x}\) as Hence…
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