TS EAMCET · Maths · Definite Integration
If \(\int_0^{\pi / 2} \tan ^{14}\left(\frac{x}{2}\right) d x=2\left[\sum_{n=1}^7 f(n)-\frac{\pi}{4}\right]\), then \(f(n)=\)
- A \(\frac{(-1)^n}{n-1}\)
- B \(\frac{(-1)^n}{2 n+1}\)
- C \(\frac{(-1)^{n+1}}{2 n-1}\)
- D \(\frac{(-1)^{n+1}}{n+1}\)
Answer & Solution
Correct Answer
(C) \(\frac{(-1)^{n+1}}{2 n-1}\)
Step-by-step Solution
Detailed explanation
Let \(u = \frac{x}{2} \Rightarrow du = \frac{1}{2} dx\). Limits: \(x=0 \Rightarrow u=0\), \(x=\frac{\pi}{2} \Rightarrow u=\frac{\pi}{4}\). \(\int_0^{\pi/2} \tan^{14}\left(\frac{x}{2}\right) dx = \int_0^{\pi/4} \tan^{14}(u) (2 du) = 2 \int_0^{\pi/4} \tan^{14}(u) du\). Given:…
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