TS EAMCET · Maths · Probability
\(\mathrm{A}, \mathrm{B}_1, \mathrm{~B}_2, \mathrm{~B}_3\) are the events in a random experiment. If \(\mathrm{P}\left(\mathrm{B}_1\right)=0.25, \mathrm{P}\left(\mathrm{B}_2\right)=0.30\), \(\mathrm{P}\left(\mathrm{B}_3\right)=0.45, \mathrm{P}\left(\frac{\mathrm{A}}{\mathrm{B}_1}\right)=0.05, \mathrm{P}\left(\frac{\mathrm{A}}{\mathrm{B}_2}\right)=0.04, \mathrm{P}\left(\frac{\mathrm{A}}{\mathrm{B}_3}\right)=0.03\), then \(\mathrm{P}\left(\frac{\mathrm{B}_2}{\mathrm{~A}}\right)=\)
- A \(\frac{6}{19}\)
- B \(\frac{8}{19}\)
- C \(\frac{12}{19}\)
- D \(\frac{5}{19}\)
Answer & Solution
Correct Answer
(A) \(\frac{6}{19}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{P}(\mathrm{A}) = \mathrm{P}(\mathrm{A}|\mathrm{B}_1)\mathrm{P}(\mathrm{B}_1) + \mathrm{P}(\mathrm{A}|\mathrm{B}_2)\mathrm{P}(\mathrm{B}_2) + \mathrm{P}(\mathrm{A}|\mathrm{B}_3)\mathrm{P}(\mathrm{B}_3)\)…
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