TS EAMCET · Maths · Three Dimensional Geometry
If the ratio of the perpendicular distances of a variable point \(P(x, y, z)\) from the \(X\)-axis and from the \(Y Z\)-plane in \(2: 3\), then the equation of the locus of \(P\) is
- A \(4 x^2-9 y^2-9 z^2=0\)
- B \(9 x^2-4 y^2-4 z^2=0\)
- C \(4 x^2-4 y^2-9 z^2=0\)
- D \(9 x^2-9 y^2-4 z^2=0\)
Answer & Solution
Correct Answer
(A) \(4 x^2-9 y^2-9 z^2=0\)
Step-by-step Solution
Detailed explanation
\(\frac{\sqrt{y^2+z^2}}{|x|}=\frac{2}{3} \Rightarrow 4 x^2-9 y^2-9 z^2=0\).
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