TS EAMCET · Maths · Ellipse
If the normal drawn at the point \((2,-1)\) to the ellipse \(x^2+4 y^2=8\) meets the ellipse again at \((a, b)\) then, \(17 a=\)
- A \(23\)
- B \(14\)
- C \(37\)
- D \(9\)
Answer & Solution
Correct Answer
(B) \(14\)
Step-by-step Solution
Detailed explanation
Equation of normal to \(\frac{x^2}{8}+\frac{y^2}{2}=1\) at \((2,-1)\) is \(\begin{aligned} & \frac{8 x}{2}-\left(\frac{2 y}{(-1)}\right)=8-2 \\ & \Rightarrow 4 x+2 y=6 \Rightarrow y=3-2 x \end{aligned}\) Solving for point of intersection…
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