TS EAMCET · Maths · Binomial Theorem
Let \(n=1 !+4 !+7 !+\ldots+400 !\). Then ten's digit of \(n\) is
- A 1
- B 6
- C 2
- D 7
Answer & Solution
Correct Answer
(B) 6
Step-by-step Solution
Detailed explanation
Given, \(n=1 !+4 !+7 !+\ldots+400 !\) \(1 !=1,4 !=24,7 !=5040,10 !=3628800\) and further the terms has last two digits \(=00\) So, \(1 !+4 !+7 !+\ldots+400 !=\ldots \ldots 65\) Here ten digit is 6 . Hence, 6 is the answer.
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