TS EAMCET · Maths · Permutation Combination
If the number of all possible permutations of the letters of the word in which the repeated letters are not together is , then
- A
- B
- C
- D
Answer & Solution
Correct Answer
(A)
Step-by-step Solution
Detailed explanation
Given word MATHEMATICS In above word Arranging other than repeated letters H,E,I,C,S is 5×4×3×2×1 =120 In between there will be 6 gaps in that we need to fill this repeated letters i.e.,=6!2×2×2=90. So total possible arrangements is…
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