TS EAMCET · Maths · Properties of Triangles
In triangle \(\mathrm{ABC}\), if \(\mathrm{A}=\frac{\pi}{3}\) and \(\mathrm{B}=\frac{\pi}{4}\) then \(\frac{a^2-b^2}{c^2}=\)
- A \(2-\sqrt{3}\)
- B \(2+\sqrt{3}\)
- C \(\sqrt{2}-1\)
- D \(\sqrt{2}+1\)
Answer & Solution
Correct Answer
(A) \(2-\sqrt{3}\)
Step-by-step Solution
Detailed explanation
Given angle \({A}=\frac{\pi}{3}\) and \({B}=\frac{\pi}{4}\) In \(\triangle {ABC}\), \( \begin{aligned} & \angle {C}=\pi-({A}+{B}) \\ & =\pi-\left(\frac{\pi}{3}+\frac{\pi}{4}\right) \\ & =\pi-\frac{7 \pi}{12}=\frac{5 \pi}{12} \end{aligned} \) Apply sine law,…
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