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TS EAMCET · Maths · Permutation Combination

If a is the number of all even divisors and b is the number of all odd divisors of the number 10800, then 2a+3b=

  1. A 72
  2. B 132
  3. C 96
  4. D 136
Verified Solution

Answer & Solution

Correct Answer

(B) 132

Step-by-step Solution

Detailed explanation

Given number is 10800 Prime factorisation of 10800 is 24×33×52 The total number of divisors =4+13+12+1 =543 =60 The number of odd divisors =13+12+1 =143 =12 The number of even divisors =60-12 =48 Here., a=48, b=12 ⇒2a+3b=248+312 =96+36 ∴ 2a+3b=132