TS EAMCET · Maths · Vector Algebra
Let \(\mathbf{a}=\hat{\mathbf{i}}+\hat{\mathbf{j}}, \mathbf{b}=\hat{\mathbf{j}}+\hat{\mathbf{k}}\) and \(\mathbf{c}=\hat{\mathbf{i}}+\hat{\mathbf{k}}\). If \(\mathbf{d}\) is a unit vector such that \(\mathbf{a} \cdot \mathbf{d}=0\) and \(\mathbf{b} \cdot(\mathbf{c} \times \mathbf{d})=0\) and \(\mathbf{d}=\)
- A \(\pm \frac{1}{\sqrt{2}}(\hat{\mathbf{i}}+\hat{\mathbf{j}})\)
- B \(\pm \frac{1}{\sqrt{2}}(\hat{\mathbf{i}}-\hat{\mathbf{j}})\)
- C \(\frac{1}{\sqrt{2}} \hat{\mathbf{i}}+\frac{1}{\sqrt{2}} \hat{\mathbf{j}}+\frac{1}{\sqrt{3}} \hat{\mathbf{k}}\)
- D \(\pm\left(\frac{1}{\sqrt{2}} \hat{\mathbf{j}}+\frac{1}{\sqrt{2}} \hat{\mathbf{k}}\right)\)
Answer & Solution
Correct Answer
(B) \(\pm \frac{1}{\sqrt{2}}(\hat{\mathbf{i}}-\hat{\mathbf{j}})\)
Step-by-step Solution
Detailed explanation
Let \(\mathbf{d}=d_1 \hat{\hat{\mathrm{I}}}+d_2 \hat{\hat{\mathrm{J}}}+d_3 \hat{\mathbf{k}}\) We have, \(\mathrm{a} \cdot \mathrm{d}=\mathbf{0}\)…
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