TS EAMCET · Maths · Probability
If the mean and variance of a binomial distribution are \(\frac{4}{3}\) and \(\frac{10}{9}\) respectively, then \(\mathrm{P}(\mathrm{X} \geq 6)=\)
- A \(\frac{41}{6^8}\)
- B \(\frac{741}{6^8}\)
- C \(1-\frac{741}{6^8}\)
- D \(1-\frac{41}{6^8}\)
Answer & Solution
Correct Answer
(B) \(\frac{741}{6^8}\)
Step-by-step Solution
Detailed explanation
\(np = \frac{4}{3}, np(1-p) = \frac{10}{9}\) \(\frac{4}{3}(1-p) = \frac{10}{9} \Rightarrow 1-p = \frac{5}{6} \Rightarrow p = \frac{1}{6}\) \(n(\frac{1}{6}) = \frac{4}{3} \Rightarrow n = 8\)…
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