TS EAMCET · Maths · Binomial Theorem
Let \(x \in \mathbf{R}\) be so small that the powers of \(x\) beyond two are insignificant and negligibly small. For such \(x\), if \((1-x)^3(2+x)^6\) is approximated by \(a+b x+c x^2\), then \(a+b+c=\)
- A -80
- B 144
- C 80
- D 127
Answer & Solution
Correct Answer
(A) -80
Step-by-step Solution
Detailed explanation
We have, \(\begin{gathered} (1-x)^3=1-3 x+3 x^2 \text { [neglecting higher term] } \\ \begin{array}{c} (2+x)^6={ }^6 C_0 2^6 x^0+{ }^6 C_1 2^5 x^1+{ }^6 C_2 2^4 x^2 \\ \text { [neglecting higher term] } \end{array} \\ =64+192 x+240 x^2 \end{gathered}\) [neglecting higher term]…
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