TS EAMCET · Maths · Straight Lines
If the lengths of the perpendiculars drawn from a point \((a, b)\) to the lines \(2 x+3 y+4=0\) and \(3 x-3 y+4=0\) are same, then the point \((a, b)\) lies on the line
- A \(x-5 y+8=0\) or \(5 x+y=0\)
- B \(x+5 y+8=0\) or \(5 x-y+8=0\)
- C \(x-5 y=0\) or \(5 x+y+8=0\)
- D \(x+5 y=0\) or \(5 x-y+8=0\)
Answer & Solution
Correct Answer
(C) \(x-5 y=0\) or \(5 x+y+8=0\)
Step-by-step Solution
Detailed explanation
\(1_1 \equiv 2 \mathrm{x}+3 \mathrm{y}+4=0\) \(1_2 \equiv 3 \mathrm{x}-2 \mathrm{y}+4=0\) \[ \because \mathrm{a}_1 \mathrm{a}_2+\mathrm{b}_1 \mathrm{~b}_2=6-6=0 \] \(\therefore 1_1\) and \(l_2\) are perpendicular. Since point \((\mathrm{a}, \mathrm{b})\) is equidistance from…
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