TS EAMCET · Maths · Complex Number
\(\sin h i x\) is equal to
- A \(i \sin x\)
- B \(\sin i x\)
- C \(-i \sin x\)
- D \(i \sin i x\)
Answer & Solution
Correct Answer
(A) \(i \sin x\)
Step-by-step Solution
Detailed explanation
We have \[ \begin{aligned} \sin h x & =\frac{e^x-e^{-x}}{2} \\ \sin h i x & =\frac{e^{i x}-e^{-i x}}{2}=i \sin x \end{aligned} \]
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