TS EAMCET · Maths · Circle
If the angle between the circles \(x^2+y^2-2 x-4 y+c=0\) and \(x^2+y^2-4 x-2 y+4=0\) is \(60^{\circ}\), then \(c=\)
- A \(\frac{3 \pm \sqrt{5}}{2}\)
- B \(\frac{6 \pm \sqrt{5}}{2}\)
- C \(\frac{7 \pm \sqrt{5}}{2}\)
- D \(\frac{9 \pm \sqrt{5}}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{7 \pm \sqrt{5}}{2}\)
Step-by-step Solution
Detailed explanation
Angle between circles…
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