TS EAMCET · Maths · Straight Lines
If \(2 x+3 y=5\) is the perpendicular bisector of the line segment joining the points \(A\left(1, \frac{1}{3}\right)\) and \(B\), then \(B\) is equal to
- A \(\left(\frac{21}{13}, \frac{49}{39}\right)\)
- B \(\left(\frac{17}{13}, \frac{31}{39}\right)\)
- C \(\left(\frac{7}{13}, \frac{49}{39}\right)\)
- D \(\left(\frac{21}{13}, \frac{31}{39}\right)\)
Answer & Solution
Correct Answer
(D) \(\left(\frac{21}{13}, \frac{31}{39}\right)\)
Step-by-step Solution
Detailed explanation
Let \(\quad l_1 \equiv 2 x+3 y=5\) Since, line \(A B \perp I_1\) \(\therefore\) Slope of \(l_1\) is \[ \begin{array}{r} m_1 \text { say }=\frac{-2}{3} \\ \therefore \text { Slope of } A B=\frac{-1}{(-2 / 3)}=\frac{3}{2} \end{array} \] Equation of line \(A B\) is…
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