TS EAMCET · Maths · Three Dimensional Geometry
If \(\bar{r}=(2-\lambda+\mu) \bar{i}+(1-\mu) \bar{j}+(2-3 \lambda+2 \mu) \bar{k}\) is the vector equation of a plane, then the equivalent cartesian equation of the plane is
- A \(3 x+y-z=5\)
- B \(3 x-y+z=5\)
- C \(-3 x+y+z=5\)
- D \(3 x-y-z=5\)
Answer & Solution
Correct Answer
(A) \(3 x+y-z=5\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Given } \bar{\gamma}=(2-\lambda+\mu) \hat{\mathrm{i}}+(1-\mu) \hat{\mathrm{j}}+(2-3 \lambda+2 \mu) \hat{\mathrm{k}} \\ & \bar{\gamma}=(2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+2 \hat{\mathrm{k}})+(-\hat{\mathrm{i}}-3 \hat{\mathrm{k}})…
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