TS EAMCET · Maths · Circle
If the line \(x+y=2\) cuts the circle \(x^2+y^2+2 x-4 y+4=0\) at two points A and B then the radius of the circle passing through \(\mathrm{A}, \mathrm{B}\) and orthogonal to \(x^2+y^2-2 x-4 y-4=0\) is
- A \(3\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(C) \(5\)
Step-by-step Solution
Detailed explanation
Let the required circle be \(S = (x^2+y^2+2x-4y+4) + \lambda(x+y-2) = 0\). \(S: x^2+y^2+(2+\lambda)x+(-4+\lambda)y+(4-2\lambda)=0\). For orthogonality with \(x^2+y^2-2x-4y-4=0\):…
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