TS EAMCET · Maths · Probability
Four numbers are chosen at random from \(\{1,2,3, \ldots, 40\}\). The probability that they are not consecutive, is
- A \(\frac{1}{2470}\)
- B \(\frac{4}{7969}\)
- C \(\frac{2469}{2470}\)
- D \(\frac{7965}{7969}\)
Answer & Solution
Correct Answer
(C) \(\frac{2469}{2470}\)
Step-by-step Solution
Detailed explanation
Probability that four of the numbers are consecutive \(=\frac{{ }^{37} C_1}{{ }^{40} C_4}\) Now, probability that four of the numbers are Now, probability that four of the numbers are consecutive \(=1-\frac{{ }^{37} C_1}{{ }^{40} C_4}\) \(=\frac{2469}{2470}\)
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