TS EAMCET · Maths · Three Dimensional Geometry
The shortest distance between the skew-lines \(\mathbf{r}=(-\hat{\mathbf{i}}+3 \hat{\mathbf{k}})+t(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\) and \(\mathbf{r}=(3 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}})+s(2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) is
- A \(\frac{10}{\sqrt{17}}\)
- B \(\frac{22}{\sqrt{17}}\)
- C 9
- D 8
Answer & Solution
Correct Answer
(B) \(\frac{22}{\sqrt{17}}\)
Step-by-step Solution
Detailed explanation
Given, lines \(\mathbf{r}=(-\hat{\mathbf{i}}+3 \hat{\mathbf{k}})+t(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\) and \(\mathbf{r}=(3 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}})+s(2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) Shortest distance…
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