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TS EAMCET · Maths · Three Dimensional Geometry

The shortest distance between the skew-lines \(\mathbf{r}=(-\hat{\mathbf{i}}+3 \hat{\mathbf{k}})+t(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\) and \(\mathbf{r}=(3 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}})+s(2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) is

  1. A \(\frac{10}{\sqrt{17}}\)
  2. B \(\frac{22}{\sqrt{17}}\)
  3. C 9
  4. D 8
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{22}{\sqrt{17}}\)

Step-by-step Solution

Detailed explanation

Given, lines \(\mathbf{r}=(-\hat{\mathbf{i}}+3 \hat{\mathbf{k}})+t(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+6 \hat{\mathbf{k}})\) and \(\mathbf{r}=(3 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}})+s(2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+2 \hat{\mathbf{k}})\) Shortest distance…