TS EAMCET · Maths · Circle
The value of \(a\), such that the power of the point \((1,6)\) with respect to the circle \(x^2+y^2+4 x-6 y-a=0\), is -16 , is
- A 7
- B 11
- C 13
- D 21
Answer & Solution
Correct Answer
(D) 21
Step-by-step Solution
Detailed explanation
Given equation of the circle is \[ x^2+y^2+4 x-6 y-a=0 \] We know that, power of point \(P(1,6)\) w.r.t. the circle \[ \begin{array}{rrrr} & x^2+y^2+4 x-6 y-a \text { is }-16 \\ \therefore & 1+36+4-36-a=-16 \\ \Rightarrow & 5-a=-16 \\ \Rightarrow & a & =21 \end{array} \]
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