TS EAMCET · Maths · Parabola
If \(P\) is a point on the parabola \(y^2=8 x\) and \(A\) is the point \((1,0)\), then the locus of the mid-point of the line segment \(A P\) is
- A \(y^2=4\left(x-\frac{1}{2}\right)\)
- B \(y^2=2(2 x+1)\)
- C \(y^2=x-\frac{1}{2}\)
- D \(y^2=2 x+1\)
Answer & Solution
Correct Answer
(A) \(y^2=4\left(x-\frac{1}{2}\right)\)
Step-by-step Solution
Detailed explanation
Let \(P\) be a point on parabola \(y^2=8 x\) whose coordinates are \(\left(2 t^2, 4 t\right)\) and \(A\) is the point \((1,0)\). Let \((x, y)\) be the mid-point of \(P\left(2 t^2, 4 t\right)\) and \(A(1,0)\).…
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