TS EAMCET · Maths · Indefinite Integration
\(\int \frac{\sin x \cdot \sec ^2 x-\tan x \cdot \sin x+\cos x}{(1-\cos 2 x)} d x=\)
- A \(\frac{1}{2}\left[\sec x-\operatorname{cosec} x-\log \left|\tan \left(\frac{x}{2}\right) \tan \left(\frac{\pi}{4}+\frac{x}{2}\right)\right|\right]+c\)
- B \(\sec x+\operatorname{cosec} x+\log \left|\frac{\tan \left(\frac{x}{2}\right)}{\tan \left(\frac{\pi}{4}+\frac{x}{2}\right)}\right|+c\)
- C \(\frac{1}{2}\left[\sec x-\operatorname{cosec} x-\log \left|\frac{\tan \left(\frac{\pi}{4}+\frac{x}{2}\right)}{\tan \left(\frac{x}{2}\right)}\right|\right]+c\)
- D \(\sec x+\operatorname{cosec} x-\log \left|\tan \left(\frac{x}{2}\right)\right|+c\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\left[\sec x-\operatorname{cosec} x-\log \left|\frac{\tan \left(\frac{\pi}{4}+\frac{x}{2}\right)}{\tan \left(\frac{x}{2}\right)}\right|\right]+c\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Take } \mathrm{I}=\int \frac{\sin x \sec ^2 x-\tan x \cdot \sin x+\cos x}{(1-\cos 2 x)} \cdot d x \\ & \mathrm{I}=\int \frac{\sin x \sec ^2 x-\tan x \cdot \sin x+\cos x}{1-1+2 \sin ^2 x} \cdot d x \\ & \mathrm{I}=\frac{1}{2}\left[\int \frac{\sec ^2…
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