TS EAMCET · Maths · Circle
The inverse point of \((1,2)\) with respect to the circle \(x^2+y^2-4 x-6 y+9=0\) is
- A \((0,0)\)
- B \((1,0)\)
- C \((0,1)\)
- D \((1,1)\)
Answer & Solution
Correct Answer
(C) \((0,1)\)
Step-by-step Solution
Detailed explanation
Inverse point of \(P(1,2)\) w.r.t. the circle is the foot of the perpendicular of \(P\) on the polar of \(P\). Given circle is \(x^2+y^2-4 x-6 y+9=0\) Polar of \(P(1,2)\) is…
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