TS EAMCET · Maths · Quadratic Equation
If \(f(x)\) is a second degree polynomial such that \(f(x) \geq 0 \forall x \in \mathbb{R}, f(-3)=0\) and \(f(0)=18\) then \(f(3)=\)
- A \(36\)
- B \(72\)
- C \(144\)
- D \(288\)
Answer & Solution
Correct Answer
(B) \(72\)
Step-by-step Solution
Detailed explanation
\(f(x) = a(x+3)^2\) \(f(0) = a(0+3)^2 = 9a = 18 \Rightarrow a = 2\) \(f(x) = 2(x+3)^2\) \(f(3) = 2(3+3)^2 = 2(6)^2 = 2(36) = 72\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If \(f:[2,3] \rightarrow R\) is defined by \(f(x)=x^3+3 x-2\), then the range \(f(x)\) is contained in the intervalTS EAMCET 2009 Easy
- If \(\alpha, \beta\) are the roots of the equation \(x^2-4 x+8=0\), then for any \(n \in N, \alpha^{2 n}+\beta^{2 n}\) equalsTS EAMCET 2015 Medium
- If \(\omega_0, \omega_1, \ldots, \omega_{n-1}\) are the \(n\)th roots of unity, then \(\left(1+2 \omega_0\right)\left(1+2 \omega_1\right)\left(1+2 \omega_2\right) \ldots\left(1+2 \omega_{n-1}\right)=\)TS EAMCET 2018 Easy
- \(\frac{d}{d x} \tan ^{-1}\left[\frac{\sqrt{1+\sin x}-\sqrt{1-\sin x}}{\sqrt{1+\sin x}+\sqrt{1-\sin x}}\right]\) is equal toTS EAMCET 2016 Easy
- The perpendicular distance from the origin to the normal drawn at any point on the curve \(x=a(\cos \theta+\theta \sin \theta), y=a(\sin \theta-\theta \cos \theta)\) isTS EAMCET 2020 Medium
- The equation of the normal at \(t=\frac{\pi}{2}\) to the curve \(\mathrm{x}=\) \(2 \sin t, y=2 \cos t\) isTS EAMCET 2023 Easy
More PYQs from TS EAMCET
- Equal amounts of two gases of molecular weights 4 and 40 are mixed. The pressure of the mixture is 1.1 atm. What will be the partial pressure of the lighter gas in the mixture?TS EAMCET 2020 Medium
- A body of mass 500 g is falling from rest from a height of 3.2 m from the ground. If the body reaches the ground with a velocity of \(6 \mathrm{~ms}^{-1}\), then the energy lost by the body due to air resistance is
\(\left(\right.\) Acceleration due to gravity \(\left.=10 \mathrm{~ms}^{-2}\right)\)TS EAMCET 2025 Medium - If \(T_4\) represents the 4th term in the expansion of \(\left(5 x+\frac{7}{x}\right)^{-3 / 2}\) and \(x \notin\left[-\sqrt{\frac{7}{5}}, \sqrt{\frac{7}{5}}\right]\), then \(\left(x^7 \sqrt{5 x}\right) T_4=\)TS EAMCET 2024 Easy
- For \(x=\frac{5}{7}\), if \(t_k\) is the first negative term in the expansion of \((1+x)^{7 / 5}\), then, \(t_1+t_2+\ldots+t_k=\)TS EAMCET 2019 Medium
- When the origin is shifted to by the translation of axes, the transformed equation of isTS EAMCET 2021 Easy
- Let x be a real number. Match the following:

TS EAMCET 2022 Easy